Problem: Given that Kb for CH3NH2 is 5.0 × 10-4 at 25 °C, what is the value of Ka for CH3NH3 at 25 °C?

FREE Expert Solution

$\overline{){{\mathbf{K}}}_{{\mathbf{w}}}{\mathbf{=}}{{\mathbf{K}}}_{{\mathbf{a}}}{\mathbf{×}}{{\mathbf{K}}}_{{\mathbf{b}}}}\phantom{\rule{0ex}{0ex}}\phantom{\rule{0ex}{0ex}}{\mathbf{K}}_{\mathbf{a}}\mathbf{=}\frac{{\mathbf{K}}_{\mathbf{w}}}{{\mathbf{K}}_{\mathbf{b}}}$

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Problem Details

Given that Kb for CH3NH2 is 5.0 × 10-4 at 25 °C, what is the value of Ka for CH3NH3 at 25 °C?