Problem: Given that Ka for HF is 6.3 × 10-4 at 25 °C, what is the value of Kb for F– at 25 °C?

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Kw=Ka×KbKb=KwKa


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Given that Ka for HF is 6.3 × 10-4 at 25 °C, what is the value of Kb for F– at 25 °C?

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