Problem: Give the systematic names of these compounds. Spelling counts!(a) CuI(s)(b) Fe2O3(s)(c) CoF2(s)(d) FeO(s)

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The rules for naming binary ionic compounds are as follows:


1. The metal keeps its name, and is named and written first.

– For transition metals, we use Roman numerals to denote its charge.


2. The nonmetal keeps its base name but has its ending change to –ide.


For CuI. We can see that the metal in the ionic compound is Cu (copper), which is a transition metal. This means it has many possible charges.



The absence of a subscript signifies that copper has a charge of +1. This means the cation is Cu+, which is named copper (I). On the other hand, the anion in the formula is I which corresponds to iodine. However, since I is an anion, we add the suffix –ide, making it iodide.


This means the name of CuI is copper (I) iodide.


For Fe2O3. We can see that the metal in the ionic compound is Fe (iron), which is a transition metal. This means it has many possible charges.


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Problem Details

Give the systematic names of these compounds. Spelling counts!

(a) CuI(s)

(b) Fe2O3(s)

(c) CoF2(s)

(d) FeO(s)

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