Problem: If the frequency factor is 1.2 x 1013/s , what is the activation barrier?The rate constant of a reaction at 33°C was measured to be 5.8 × 10-2 /s.

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k=Ae-EaRTln k=ln Ae-EaRTln k=ln A+(-EaRT)(ln k-ln A) (-RT)=-EaRT(-RT)Ea=(-RT)(ln k-ln A) 

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Problem Details

If the frequency factor is 1.2 x 1013/s , what is the activation barrier?
The rate constant of a reaction at 33°C was measured to be 5.8 × 10-2 /s.

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