In this problem, we are asked to **calculate for [H ^{+}]** for each of the following solutions.

A. **[OH ^{-}] = 4.8x10^{-4 }M**

• **pOH**:

$\overline{){\mathbf{pOH}}{\mathbf{=}}{\mathbf{-}}{\mathbf{log}}\mathbf{\left[}{\mathbf{OH}}^{\mathbf{-}}\mathbf{\right]}}\phantom{\rule{0ex}{0ex}}\mathbf{pOH}\mathbf{=}\mathbf{-}\mathbf{log}\mathbf{(}\mathbf{4}\mathbf{.}\mathbf{8}\mathbf{\times}{\mathbf{10}}^{\mathbf{-}\mathbf{4}}\mathbf{)}$

** pOH = 3.32 M**

Calculate [H^{+}] for each of the following solutions.

[OH^{-}] = 4.8x10^{-4 }M

[OH^{-}] = 8.3x10^{-9 }M

A solution in which [OH^{-}] is 140 times greater than [H^{+}].

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What scientific concept do you need to know in order to solve this problem?

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