# Problem: Use the data provided to calculate benzaldehyde's heat of vaporization.Vapor Pressure (torr)                      Temperature (K)             14.0                                                  345.0         567                                                   441.0Heat of vaporization = ______  kJ/mol

###### FREE Expert Solution

We’re being asked to determine the heat of vaporization of a substance. We’re given the vapor pressure at two different temperatures. For this problem, we can use the Clausius-Clapeyron Equation:

$\overline{){\mathbf{ln}}\mathbf{\left(}\frac{{\mathbf{P}}_{\mathbf{2}}}{{\mathbf{P}}_{\mathbf{1}}}\mathbf{\right)}{\mathbf{=}}{\mathbf{-}}\frac{\mathbf{∆}{\mathbf{H}}_{\mathbf{vap}}}{\mathbf{R}}\mathbf{\left[}\frac{\mathbf{1}}{{\mathbf{T}}_{\mathbf{2}}}\mathbf{-}\frac{\mathbf{1}}{{\mathbf{T}}_{\mathbf{1}}}\mathbf{\right]}}$

where:

P1 = vapor pressure at T1

P2 = vapor pressure at T2

ΔHvap = heat of vaporization (in J/mol)

R = gas constant (8.314 J/mol•K)

T1 and T2 = temperature (in K). ###### Problem Details

Use the data provided to calculate benzaldehyde's heat of vaporization.

Vapor Pressure (torr)                      Temperature (K)

14.0                                                  345.0

567                                                   441.0

Heat of vaporization = ______  kJ/mol