We're asked to calculate the value of Ksp for Lead (II) chloride, PbCl2 if its solubility in water is 0.45 g/100 mL.
PbCl2 is an ionic compound and will dissociate in water by the reaction:
The charge of lead, Pb = +2 (from Roman numeral = II)
PbCl2 (s) ⇌ Pb2+ (aq) + 2 Cl- (aq)
The molar concentration of PbCl2 is:
0.016 mol/L 0.016 M
We can construct an ICE table for this dissociation.
The solubility of lead(II) chloride is 0.45 g/100 mL of solution. What is the Ksp of PbCl2?
A) 4.9 x 10-2
B) 1.7 x 10-5
C) 8.5 x 10-6
D) 4.2 x 10-6
E) <1.0 x 10-6
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