# Problem: Enough of a monoprotic acid is dissolved in water to produce a 0.0192 M solution. The pH of the resulting solution is 2.53. Calculate the Ka for the acid.

###### FREE Expert Solution

The dissociation of a monoprotic weak acid (HA) is as follows:

HA(aq) + H2O(l)  H3O+(aq) + A(aq)

From this, we can construct an ICE table. Remember that liquids are ignored in the ICE table and Ka expression.

###### Problem Details

Enough of a monoprotic acid is dissolved in water to produce a 0.0192 M solution. The pH of the resulting solution is 2.53. Calculate the Ka for the acid.