To calculate # of atoms given mass:
Avogadro’s number = 6.022 x 1023 entities
entities = atoms, ions, molecules, particles, formula units
Cu(NO3)2: 1 Cu x 63.55 g/mol = 63.55 g/mol
2 N x 14.00 g/mol = 28.00 g/mol
6 O x 16.00 g/mol = 96.00 g/mol (multiply O by its subscript: 3 x 2 = 6)
Sum = 187.55 g/mol
How many nitrogen atoms are in 10.2 g of copper(II) nitrate?
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