Problem: How many nitrogen atoms are in 10.2 g of copper(II) nitrate?

FREE Expert Solution

To calculate # of atoms given mass:


          Avogadro’s number = 6.022 x 1023 entities

                                      entities = atoms, ions, molecules, particles, formula units


Molar Mass: 


Cu(NO3)2: 1 Cu x 63.55 g/mol = 63.55 g/mol

2 N  x 14.00 g/mol = 28.00 g/mol 
6 O  x 16.00 g/mol = 96.00 g/mol  (multiply O by its subscript: 3 x 2 = 6)

____________________________
                         Sum = 
187.55 g/mol


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Problem Details

How many nitrogen atoms are in 10.2 g of copper(II) nitrate?



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