We are asked to label all the bonds in NF3.
Step 1: Determine the central atom in this molecule.
• N→ less electronegative atom than F → central atom
Step 2: Calculate the total number of valence electrons present.
Group Valence Electrons
N 5A 1 × 5 e– = 5 e–
F 7A 3 × 7 e– = 21 e–
Total: 26 valence e–
Label all bonds in NF3.
Hybridization of N atom in NF3 is sp3
Lone pair in p orbital
Lone pair in s orbital
δ: N(p) - F(sp3)
δ: N(p) - F(p)
π: N(p) - F(p)
Lone pair in sp3 orbital
δ: N(sp3) - F(p)
π: N(sp3) - F(p)
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Valence Shell Electron Pair Repulsion Theory concept. If you need more Valence Shell Electron Pair Repulsion Theory practice, you can also practice Valence Shell Electron Pair Repulsion Theory practice problems.
What professor is this problem relevant for?
Based on our data, we think this problem is relevant for Professor Gunasekera's class at UIUC.