# Problem: Calculate the solubility of Mn (OH)2 in grams per liter when buffered at pH (a) 7.0 (b) 9.5 (c) 11.8

###### FREE Expert Solution

Given: Mn(OH)2(s) ⇌ Mn2+(aq) + 2 OH(aq); Ksp = 1.6 × 10–13

Ksp Expression:

$\overline{){{\mathbf{K}}}_{{\mathbf{sp}}}{\mathbf{=}}\mathbf{\left[}{\mathbf{Mn}}^{\mathbf{2}\mathbf{+}}\mathbf{\right]}{\mathbf{\left[}{\mathbf{OH}}^{\mathbf{-}}\mathbf{\right]}}^{{\mathbf{2}}}}$

ICE Chart:

Recall:

$\overline{){\mathbf{\left[}}{{\mathbf{OH}}}^{{\mathbf{-}}}{\mathbf{\right]}}{\mathbf{=}}{{\mathbf{10}}}^{\mathbf{-}\mathbf{pOH}}}\phantom{\rule{0ex}{0ex}}\overline{){\mathbf{pOH}}{\mathbf{=}}{\mathbf{14}}{\mathbf{-}}{\mathbf{pH}}}$

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###### Problem Details

Calculate the solubility of Mn (OH)2 in grams per liter when buffered at pH

(a) 7.0

(b) 9.5

(c) 11.8

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Based on our data, we think this problem is relevant for Professor Bazzi & Savu's class at UMD.