Problem: Calculate the pH of the resulting solution if 32.0 mL of 0.320 M HCl(aq) is added to 37.0 mL of 0.320 M NaOH (aq).

FREE Expert Solution

Given: 32.0 mL of 0.320 M HCl(aq) + 37.0 mL of 0.320 M NaOH(aq)


Reaction: HCl(aq) + NaOH(aq) → NaCl(aq) + H2O(l)


Calculating moles of each:

32.0 mL×1 L10-3 mL×0.320 mol HCl1 L = 0.01024 mol HCl


37.0 mL×1 L10-3 mL×0.320 mol NaOH1 L = 0.01184 mol NaOH


Since mol HCl < mol NaOH

0.01184 mol NaOH – 0.01024 mol HCl = 1.6 × 10–3 mol NaOH

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Problem Details

Calculate the pH of the resulting solution if 32.0 mL of 0.320 M HCl(aq) is added to 37.0 mL of 0.320 M NaOH (aq).

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