Problem: A researcher studying the nutritional value of a new candy places a 5.80-gram sample of the candy inside a bomb calorimeter and combusts it in excess of oxygen. The observed temperature increase is 2.92 degrees Celcius. If the heat capacity of the calorimeter is 36.00 kJ*K-1, how many nutritional Calories are there per gram of the candy?

FREE Expert Solution

Recall that heat can be calculated using the following equation:

q=cT

q = heat, J

+qabsorbs heat
–qloses heat
 c = specific heat capacity = kJ/K
 ΔT = Tf – Ti = (°C or K)


Given:

ΔT= 2.92°C or K (either unit is equivalent for temperature change)
c = 36.00 kJ/K

q = ??


q=cTq=(36.00 kJ/K)(2.92 K)

q = 105.12 kJ


100% (315 ratings)
View Complete Written Solution
Problem Details

A researcher studying the nutritional value of a new candy places a 5.80-gram sample of the candy inside a bomb calorimeter and combusts it in excess of oxygen. The observed temperature increase is 2.92 degrees Celcius. If the heat capacity of the calorimeter is 36.00 kJ*K-1, how many nutritional Calories are there per gram of the candy?

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Constant-Volume Calorimetry concept. You can view video lessons to learn Constant-Volume Calorimetry. Or if you need more Constant-Volume Calorimetry practice, you can also practice Constant-Volume Calorimetry practice problems.