Recall that heat can be calculated using the following equation:
q = heat, J
• +q → absorbs heat
• –q → loses heat
c = specific heat capacity = kJ/K
ΔT = Tf – Ti = (°C or K)
ΔT= 2.92°C or K (either unit is equivalent for temperature change)
c = 36.00 kJ/K
q = ??
q = 105.12 kJ
A researcher studying the nutritional value of a new candy places a 5.80-gram sample of the candy inside a bomb calorimeter and combusts it in excess of oxygen. The observed temperature increase is 2.92 degrees Celcius. If the heat capacity of the calorimeter is 36.00 kJ*K-1, how many nutritional Calories are there per gram of the candy?
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