**Step 1: Calculate the mass defect (Δm).**

**Given:**

• mass ^{48}Ti = 47.9359 amu

atomic # Ti = **# of protons = 22**

mass # = 48

# of neutrons = 48 - 22

**# of neutrons = 26**

• mass of proton = 1.007276 amu

• mass neutron = 1.008665 amu

$\mathbf{\u2206}\mathbf{m}\mathbf{=}\mathbf{(}\mathbf{neutrons}\mathbf{+}\mathbf{protons}\mathbf{)}\mathbf{-}\mathbf{Ti}$$\mathbf{\u2206}\mathbf{m}\mathbf{=}[26\left(1.008665\mathrm{amu}\right)+22\left(1.007276\mathrm{amu}\right)]\mathbf{-}\mathbf{47}\mathbf{.}\mathbf{9359}\mathbf{}\mathbf{amu}\phantom{\rule{0ex}{0ex}}\mathbf{\u2206}\mathbf{m}\mathbf{=}\mathbf{48}\mathbf{.}\mathbf{385362}\mathbf{}\mathbf{amu}\mathbf{-}\mathbf{47}\mathbf{.}\mathbf{9359}\mathbf{}\mathbf{amu}$

**Δ****m = 0.449462 amu**

**Step 2: Calculate the mass defect (Δm) in kg.**

**1 amu = 1.6606x10 ^{-27} kg**

The nuclear mass of ^{48}Ti is 47.9359 amu. Calculate the binding energy per nucleon for ^{48}Ti.

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Mass Defect concept. If you need more Mass Defect practice, you can also practice Mass Defect practice problems.