# Problem: Construct the octahedral crystal-field splitting diagram for the metal in each species. a) V(H2O)63+ b) Co(CN)63- c) Mn(H2O)62+

###### FREE Expert Solution
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###### FREE Expert Solution

Octahedral crystal-field splitting diagram → d-orbital electrons

• high-spin - electrons can occupy the upper level (eg)
• low-spin - electrons can pair up with the electrons on the lower level (t2g)

Recall that:

• weak field ligands → high spin  lowΔ or crystal field splitting energy values
• strong field ligands → low spin  highΔ or crystal field splitting energy values

a) V(H2O)63+

• Neutral state: V: [Ar] 4s23d3
• Nearest noble gas before V is Ar
• Excited state:

▪ charge = +3: means that it lost 3 electrons:
subtract the electrons from the highest numbered orbital or higher energy orbital: 4s first then 3d

V3+:  [Ar]4s23d3-1

V3+: [Ar] 3d2

83% (193 ratings)
###### Problem Details

Construct the octahedral crystal-field splitting diagram for the metal in each species.

a) V(H2O)63+

b) Co(CN)63-

c) Mn(H2O)62+