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# Problem: A 0.15 M solution of BaCl2 contains:A) 0.15 M Ba2+ ions and 0.15 M Cl- ions. B) 0.15 M Ba2+ ions and 0.30 M Cl- ions. C) 0.30 M Ba2+ ions and 0.15 M Cl- ions. D) 0.30 M Ba2+ ions and 0.30 M Ci-ions. E) none of the above

###### FREE Expert Solution

We’re being asked to calculate the molarity (M) of Ba2+ and Cl in 0.15 M BaCl2 solution. Recall that:

• Dissociation of BaCl2: BaCl2(s)  Ba2+(aq) + 2 Cl(aq)

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###### Problem Details

A 0.15 M solution of BaCl2 contains:

A) 0.15 M Ba2+ ions and 0.15 M Cl- ions.

B) 0.15 M Ba2+ ions and 0.30 M Cl- ions.

C) 0.30 M Ba2+ ions and 0.15 M Cl- ions.

D) 0.30 M Ba2+ ions and 0.30 M Ci-ions.

E) none of the above

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Based on our data, we think this problem is relevant for Professor Nievaldo's class at SBCC.