Problem: A 0.15 M solution of BaCl2 contains:A) 0.15 M Ba2+ ions and 0.15 M Cl- ions. B) 0.15 M Ba2+ ions and 0.30 M Cl- ions. C) 0.30 M Ba2+ ions and 0.15 M Cl- ions. D) 0.30 M Ba2+ ions and 0.30 M Ci-ions. E) none of the above

FREE Expert Solution

We’re being asked to calculate the molarity (M) of Ba2+ and Cl in 0.15 M BaCl2 solution. Recall that:


Molarity (M)=moles of soluteLiters of solution


• Dissociation of BaCl2: BaCl2(s)  Ba2+(aq) + 2 Cl(aq)


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Problem Details

A 0.15 M solution of BaCl2 contains:

A) 0.15 M Ba2+ ions and 0.15 M Cl- ions. 

B) 0.15 M Ba2+ ions and 0.30 M Cl- ions. 

C) 0.30 M Ba2+ ions and 0.15 M Cl- ions. 

D) 0.30 M Ba2+ ions and 0.30 M Ci-ions. 

E) none of the above

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What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Molarity concept. You can view video lessons to learn Molarity. Or if you need more Molarity practice, you can also practice Molarity practice problems.

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Based on our data, we think this problem is relevant for Professor Nievaldo's class at Santa Barbara City College.