Problem: Compute the equilibrium constant for the spontaneous reaction between Cd2+(aq) and Zn(s). Express your answer using two significant figures.

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Cd2+ (aq) + Zn (s) → Cd (s) + Zn2+

↓ E° → oxidation → anode

↑ E° → reduction → cathode


Anode: Zn2+ (aq) + 2 e→ Zn (s)                 E = -0.763 V

Cathode: Cd2+ (aq) + 2e- → Cd (s)              E = -0.403 V



E°cell=E°cathode-E°anode  

E°cell = -0.403 - 0.763 = 0.36 V


Calculate Ecell.

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Problem Details

Compute the equilibrium constant for the spontaneous reaction between Cd2+(aq) and Zn(s). Express your answer using two significant figures.

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