# Problem: In the concentration cell created using Ag/Ag+, what is the value of E?

###### FREE Expert Solution

concentration cell is an electrolytic cell that is comprised of two half-cells with the same electrodes, but different concentrations.

Ag(s)  Ag+(aq) + 1 e        E˚ = –0.80 V  Anode/Oxidation (reverse of reduction → negative sign)

Ag+(aq) + 1 e Ag(s)         = 0.80 V   Cathode/Reduction

$\overline{){\mathbf{E}}{{\mathbf{°}}}_{{\mathbf{cell}}}{\mathbf{=}}{\mathbf{E}}{{\mathbf{°}}}_{{\mathbf{cathode}}}{\mathbf{-}}{\mathbf{E}}{{\mathbf{°}}}_{{\mathbf{anode}}}}$

###### Problem Details

In the concentration cell created using Ag/Ag+, what is the value of E?