To calculate ΔE for the reaction: Na(g)+Cl(g) → Na+(g)+Cl-(g)
First ionization energy → removing the first valence electron from neutral Na
N→ Na+ + e- I. E. = 496 kJ/mol
Electron affinity is the energy change from the addition of 1 e– to a gaseous element/ion.
Cl(g) + e- → Cl-(g) E. A. = -349 kJ/mol
Using the data in the figures above calculate ΔE for the reaction Na(g)+Cl(g)?Na+(g)+Cl?(g)