Problem: What concentration of the lead ion, Pb2+ , must be exceeded to precipitate PbF2 from a solution that is 1.00?10?2 M in the fluoride ion, F? ? Ksp for lead(II) fluoride is 3.3?10?8 .

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For this problem, we’re being asked to calculate the concentration of Pb2+ needed in order to precipitate PbF2 from a 1.00 x 10-2 M F- solution.


Dissociation reaction: PbF2(s) ⇌ Pb2+(aq) + 2F–(aq)


Step 1: ICE Chart




Step 2: Ksp expression


Ksp=productsreactants=[Pb2+][F-]2

Note that each concentration is raised by the stoichiometric coefficient

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Problem Details

What concentration of the lead ion, Pb2+ , must be exceeded to precipitate PbF2 from a solution that is 1.00?10?2 M in the fluoride ion, F? ? Ksp for lead(II) fluoride is 3.3?10?8 .

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