Using Lewis formulas, assign oxidation states to t...

Question

Using Lewis formulas, assign oxidation states to the atoms ina) H2CO (g)H =C =O =b) CH3OH (l)C =H =O =H =    (last H)

Jules Bruno · Accepted Answer

a) H2COStep 1: Calculate total number of electrons:            Group            ValenceelectronsH         1A                   2 x 1 e- = 2 e-C         4A                   1 x 4 e- = 4 e-O         6A                   1 x 6 e- =6 e-                          Total:  12 e-[readmore]Step 2: Lewis structureStep 3: Determine Oxidation stateO.S. of H = +1O.S. of O = -2O.S. of C + 2(O.S. of H) + O.S. of O = 0O.S. of C + 2(+1) + (-2) = 0O.S. of C + (+2) + (-2) = 0O.S. of C  = 0b) CH3OHStep 1: Calculate total number of electrons:            Group            ValenceelectronsH         1A                   4 x 1 e- = 4 e-C         4A                   1 x 4 e- = 4 e-O         6A                   1 x 6 e- =6 e-                          Total:  14 e-Step 2: Lewis structureStep 3: Determine Oxidation stateO.S. of H = +1O.S. of O = -2O.S. of H (last) = +1O.S. of C + 3(O.S. of H) + O.S. of O + O.S. of H(last) = 0O.S. of C + 3(+1) + (-2) + (+1) = 0O.S. of C + (+3) + (-2) + (+1) = 0O.S. of C + (+2) = 0O.S. of C = -2

Problem: Using Lewis formulas, assign oxidation states to the atoms ina) H2CO (g)H =C =O =b) CH3OH (l)C =H =O =H = (last H)

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Problem: Using Lewis formulas, assign oxidation states to the atoms ina) H2CO (g)H =C =O =b) CH3OH (l)C =H =O =H = (last H)

FREE Expert Solution

Problem Details

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