Let’s first write the balanced reaction between HCl and NaOH:
▪ HCl → strong binary acid
▪ NaOH → (OH- with Group 1A ion) → strong base
▪ the reaction between a strong base and strong acid → no need to create an ICE chart
Balanced reaction: HCl(aq) + NaOH(aq) → H2O(l) + NaCl(aq)
a) 35.0 mL of 0.350 M HCl(aq) is added to 25.0 mL of 0.450 M NaOH(aq)
Step 1: Calculate the initial amount (in moles) of the HCl and NaOH
Calculate the pH of the resulting solution if 35.0 mL of 0.350 M HCl(aq) is added to
a) 25.0 mL of 0.450 M NaOH(aq)
b) 45.0 mL of 0.350 M NaOH(aq).
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Strong Acid Strong Base Titrations concept. You can view video lessons to learn Strong Acid Strong Base Titrations. Or if you need more Strong Acid Strong Base Titrations practice, you can also practice Strong Acid Strong Base Titrations practice problems.