Let’s first write the balanced reaction between HCl and NaOH:
▪ HCl → strong binary acid
▪ NaOH → (OH- with Group 1A ion) → strong base
▪ the reaction between a strong base and strong acid → no need to create an ICE chart
Balanced reaction: HCl(aq) + NaOH(aq) → H2O(l) + NaCl(aq)
a) 35.0 mL of 0.350 M HCl(aq) is added to 25.0 mL of 0.450 M NaOH(aq)
Step 1: Calculate the initial amount (in moles) of the HCl and NaOH
Calculate the pH of the resulting solution if 35.0 mL of 0.350 M HCl(aq) is added to
a) 25.0 mL of 0.450 M NaOH(aq)
ph=____
b) 45.0 mL of 0.350 M NaOH(aq).
ph= ______
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