a. 3 Fe2+(aq) + 2 Cr(s) ⟶ 3 Fe(s) + 2 Cr3+(aq)
Oxidation: 2Cr3+(aq) + 6e− ⟶ 2Cr(s) E° = -0.73V
Reduction: 3 Fe2+(aq)+ 6e− ⟶ 3Fe(s) E°= −0.45V
Based on the sign of E°cell, classify these reactions as spontaneous or nonspontaneous as written. Assume standard conditions.
3Fe2+(aq) + 2Cr(s) → 3Fe(s) + 2Cr3+(aq)
Al3+(aq) + 3Na(s) → Al(s) +3Na+(aq)
Zn2+(aq) + Sn(s) → Zn(s) + Sn2+(aq)
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