MM of Mg is 24.31 g/mol; MM of Mg(NO3)2 is 148.3 g Mg(NO3)2
Assuming an efficiency of 30.60%, calculate the actual yield of magnesium nitrate formed from 140.2 g of magnesium and excess copper(II) nitrate.
Mg + Cu (NO3)2 → Mg(NO3)2 + Cu
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