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Problem: Combining 0.254 mol of Fe2O3 with excess carbon produced 12.8 g of Fe.Fe2O3 + 3C → 2Fe + 3COWhat is the actual yield of iron in moles?What was the theoretical yield of iron in moles?What was the percent yield?

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MM of Fe2O3 is 159.69; MM of Fe is 55.85 g/mol

a. moles of Fe:

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Problem Details

Combining 0.254 mol of Fe2O3 with excess carbon produced 12.8 g of Fe.

Fe2O3 + 3C → 2Fe + 3CO

What is the actual yield of iron in moles?

What was the theoretical yield of iron in moles?

What was the percent yield?

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