Complete and balance the following equations, and ...

Question

Complete and balance the following equations, and identify the oxidizing and reducing agents.

MnO−4(aq)+CH3OH(aq)→Mn2+(aq)+HCO2H(aq) (acidic solution)

Express your answer as a chemical equation. Identify all of the phases in your answer.

Jules Bruno · Accepted Answer

To balance the given oxidation-reduction reaction (acidic solution):MnO4–(aq) +  CH3OH(aq)   →  Mn2+(aq) + HCO2H(aq)Step 1: Separate into two half-reactions:MnO4–(aq)→ Mn2+(aq)                                                  CH3OH(aq) → HCO2H(aq)(Mn: balanced)                                                                           (C: balanced)[readmore]Step 2: Balance oxygen by adding H2O to the side that needs oxygen (1 O: 1 H2O):MnO4–(aq)→ Mn2+(aq)+ 4 H2O(l)                                  CH3OH(aq) + H2O(l)→ HCO2H(aq)(needs 4 O on the product side)                                               (needs 1 O on the reactant side)Step 3: Balance hydrogen by adding H+ to the side that needs hydrogen. (1 H: 1 H+):MnO4–(aq)+ 8 H+(aq) → Mn2+(aq)+ 4 H2O(l)             CH3OH(aq) + H2O(l)→ HCO2H(aq)+ 4 H+(aq)(needs 8 H on the reactant side)                                              (needs 4 H on the product side)Step 4: Balance the charges: add electrons to the more positive side (or less negative side):• For species that are neutral: oxidation state = 0• For ions (or species with charges): oxidation state = charge of the ion• The reactant side and the product side should have an equal overall charge (after adding electrons)MnO4–(aq)+ 8 H+(aq) → Mn2+(aq)+ 4 H2O(l)               CH3OH(aq) + H2O(l)→ HCO2H(aq)+ 4 H+(aq)Reactants                  Products                                             Reactants                ProductsMnO4– = –1                Mn2+ = +2                                        CH3OH– =0              HCO2H = 08 H+ = + 8                   4 H2O = 0                                          H2O = 0                       4 H+ = +4     +5e– = –5                                                                                                                  + 4e– = –4––––––––––                ––––––––––                                    ––––––––––                ––––––––––Overall = +2               Overall = +2                                     Overall = 0                  Overall = 0Step 5: Balance electrons on the two half-reactions:• Multiply the reactions so both half-reactions have the same number of electrons• Electrons should cancel in the overall reaction(MnO4–(aq)+ 8 H+(aq) + 5 e– → Mn2+(aq)+ 4 H2O(l)) × 4→ multiply by 4 to get 20 e–(CH3OH(aq) + H2O(l)→ HCO2H(aq)+ 4 H+(aq)+ 4 e– ) × 5 → multiply by 5 to get 20 e–This gives us:4 MnO4–(aq)+ 32 H+(aq) + 20 e– → 4 Mn2+(aq)+ 16 H2O(l)gained electrons (reactant side) → reduction5 CH3OH(aq) + 5 H2O(l)→ 5 HCO2H(aq)+ 20 H+(aq)+ 20 e–lost electrons (product side) → oxidationTo identify oxidizing agent and reducing agent:Recall the mnemonic for redox reactions:Loss Electrons →Oxidation →Reducing AgentGain Electrons →Reduction →Oxidizing AgentOxidizing agent: MnO4–Reducing agent: CH3OHStep 6: Get the overall reaction by adding the two reactions:• Species that appear in both reactions on opposite sides are subtracted4 MnO4–(aq)+ 32 H+(aq) + 20 e– → 4 Mn2+(aq)+ 16 H2O(l)        5 CH3OH(aq) + 5 H2O(l)→ 5 HCO2H(aq)+ 20 H+(aq)+ 20 e–__________________________________________________________________4 MnO4–(aq) + 5 CH3OH(aq)+ 12 H+ (aq) →  4 Mn2+(aq) +5 HCO2H(aq)+ 11 H2O (l)Balanced redox reaction:4 MnO4–(aq)+ 5 CH3OH (aq) +12H+(aq →4 Mn2+(aq) + 5 HCO2H(aq)+ 11 H2O(l)

Problem: Complete and balance the following equations, and identify the oxidizing and reducing agents.MnO−4(aq)+CH3OH(aq)→Mn2+(aq)+HCO2H(aq) (acidic solution)Express your answer as a chemical equation. Identify all of the phases in your answer.

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Problem: Complete and balance the following equations, and identify the oxidizing and reducing agents.MnO−4(aq)+CH3OH(aq)→Mn2+(aq)+HCO2H(aq) (acidic solution)Express your answer as a chemical equation. Identify all of the phases in your answer.

FREE Expert Solution

Problem Details

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