To balance the given oxidation-reduction reaction (acidic solution):
Cr2O72–(aq) + I–(aq)→ Cr3+ (aq)+ IO3–(aq)
Step 1: Separate into two half-reactions:
Cr2O72–→ Cr3+ I–(aq)→ IO3–(aq)
Step 2: Balance the non-hydrogen and non-oxygen elements first:
Cr2O72–→ 2Cr3+ I–(aq)→ IO3–(aq)
(Cr: balanced) (I: balanced)
Complete and balance the following equations.
Cr2O2−7(aq)+I−(aq)→Cr3+(aq)+IO−3(aq) (acidic solution)
Express your answer as a chemical equation. Identify all of the phases in your answer.
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