To calculate the pH for titration of different amounts of NaOH with 25.0 mL of 0.250 HCl:
Step 1: Reaction between HCl and KOH:
▪ HCl → strong binary acid
▪ NaOH → (OH- with Group 1A ion) → strong base
▪ no need to create an ICE chart
Balanced reaction: HCl(aq) + NaOH(aq) → H2O(l) + NaCl(aq)
Calculate the pH of the resulting solution if 25.0 mL of 0.250 M HCl(aq) is added to
(a) 30.0 mL of 0.250 M NaOH(aq). pH___________
(b) 35.0 mL of 0.300 M NaOH(aq). pH___________
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What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Strong Acid Strong Base Titrations concept. You can view video lessons to learn Strong Acid Strong Base Titrations. Or if you need more Strong Acid Strong Base Titrations practice, you can also practice Strong Acid Strong Base Titrations practice problems.
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Based on our data, we think this problem is relevant for Professor Freeman's class at SCAR.