i = 1 → non-electrolyte or compounds that do not ionize
i = # of ions produce → electrolytes or compounds that 100% ionize
For an aqueous solution of HF, determine the van't Hoff factor assuming...
0% ionization 100% ionization
A solution is made by dissolving 0.0300 mol of HF in 1.00 kg of water. The solution was found to freeze at -0.0644 °C. Calculate the value of i and estimate the percent ionization of HF in this solution.
so HF is
a) 0% ionized
b) between 0% and 50% ionized
c) 50% ionized
d) between 50% and 100% ionized
e) 100% ionized
in this solution.
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