Problem: Given that E°cell for the reaction is -0.04 VFe3+(aq) + 3e- → Fe(s)      ε° = -0.04 VCalculate the solubility product constant for FePO4(s) at 25 °C.FePO4(s) + 3e- → Fe(s) + PO43-(aq)        ε° = -0.47 V

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Given that E°cell for the reaction is -0.04 V

Fe3+(aq) + 3e- → Fe(s)      ε° = -0.04 V

Calculate the solubility product constant for FePO4(s) at 25 °C.

FePO4(s) + 3e- → Fe(s) + PO43-(aq)        ε° = -0.47 V


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