Given that E°cell for the reaction is -0.04 V
Fe3+(aq) + 3e- → Fe(s) ε° = -0.04 V
Calculate the solubility product constant for FePO4(s) at 25 °C.
FePO4(s) + 3e- → Fe(s) + PO43-(aq) ε° = -0.47 V
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