Problem: The Kw for water at 0 C is 0.12 x 10^-14 . Calculate the pH of a neutral aqueous solution at 0°C?

FREE Expert Solution

The relationship between [H+] and [OH-] is connected by the following equation:

Kw=H+OH-

Kw = autoionization constant of water

Kw = 0.12×10-14 at T = 0°C

A neutral solution has [H+] = [OH-]. Denoting these concentrations as x, we can determine the concentrations of these ions:

Kw=[H+][OH-]0.12×10-14=(x)(x)0.12×10-14=x2x2=0.12×10-14

x = [H3O+] = 3.46×10-8

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Problem Details

The Kw for water at 0 C is 0.12 x 10^-14 . Calculate the pH of a neutral aqueous solution at 0°C?