Step 1: Plot 1/v_{0} vs 1/S

$\overline{)\frac{\mathbf{1}}{{\mathbf{v}}_{\mathbf{0}}}{\mathbf{}}{\mathbf{=}}\mathbf{(}\mathbf{}\frac{{\mathbf{K}}_{\mathbf{m}}}{{\mathbf{V}}_{\mathbf{max}}}\mathbf{\xb7}\frac{\mathbf{1}}{\mathbf{S}}\mathbf{)}{\mathbf{}}{\mathbf{+}}{\mathbf{}}\frac{\mathbf{1}}{{\mathbf{V}}_{\mathbf{max}}}}$

y = m x + b

The data below were collected for an enzyme-catalyzed reaction.

Determine Vmax and Km for this reaction. V_{max} = K_{m} = for this reaction.

This graph is provided for your use only. It will not be graded. (It is not necessary to use a graph to answer.)