# Problem: What is the pH of a 0.38 M solution of sodium propionate, NaC3H5O2, at 25°C? (For propionic acid, HC3H5O2, Ka = 1.3 × 10–5 at 25°C.)A) 6.11B) 4.77C) 11.10D) 7.89E) 9.23

###### FREE Expert Solution

We are being asked to calculate the pH of a 0.38 M solution of sodium propionate, NaC3H5O2, at 25°C.

We're going to calculate for the pH using the following steps:

Step 1: Write the equilibrium reaction.
Step 2: Construct an ICE chart for the equilibrium reaction.
Step 3: Calculate for the equilibrium concentration of OH-.
Step 4: Calculate for pOH.
Step 5: Calculate for pH.

Step 1: Write the equilibrium reaction.

NaC3H5O2 is a salt and it will break up in the solution:

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###### Problem Details

What is the pH of a 0.38 M solution of sodium propionate, NaC3H5O2, at 25°C? (For propionic acid, HC3H5O2, Ka = 1.3 × 10–5 at 25°C.)

A) 6.11

B) 4.77

C) 11.10

D) 7.89

E) 9.23