We’re being asked to calculate the pH of a 0.24 M aniline solution given the Kb of 3.8x10-10
In this case, we have to follow the steps:
Step 1. Setup the equilibrium and ICE chart
Step 2. Calculate x or OH-
Step 3. Calculate pH
Step 1. The formula for aniline is C6H5NH2 and its reaction with water is:
C6H5NH2 + H2O ⇌ C6H5NH3+ + OH-
We need to write an ICE chart to determine the concentration of OH- which we will use to get the pOH, then the pH.
We know that the equilibrium constant expression, Kb is:
What is the pH of a 0.24 M solution of aniline (C6H5NH2, Kb = 3.8 × 10–10) at 25°C?