For this problem, we have to calculate the Kb of CN- using the Ka at 6.8x10-10
Recall that Ka and Kb is related using the autoionization constant (1x10-14):
The Ka for hydrocyanic acid, HCN, is 6.8 × 10–10. What is Kb for the cyanide ion, CN-?
A) 1.5 × 10–11
B) 1.5 × 10–5
C) 1.5 × 109
D) 6.8 × 1010
E) 6.8 × 10–24
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