For this problem, we have to calculate the pH of 0.02 M KOH

KOH is a strong base (hydroxide of a Group 1A metal) which dissociates as:

KOH (aq) → K^{+} (aq) + OH^{-} (aq)

Calculating the [OH-]:

$\left[{\mathrm{OH}}^{-}\right]\mathbf{}\mathbf{=}\mathbf{}(0.02\frac{\overline{)\mathrm{mol}\mathrm{KOH}}}{1L})\left(\frac{1\mathrm{mol}{\mathrm{OH}}^{-}}{1\overline{)\mathrm{mol}\mathrm{KOH}}}\right)$

[OH^{-}] = 0.02 M

Calculating pOH:

Calculate the pH of a 0.02 M solution of KOH.

A) 2.7

B) 0.02

C) 12.3

D) 2.0

E 12.0

Frequently Asked Questions

What scientific concept do you need to know in order to solve this problem?

Our tutors have indicated that to solve this problem you will need to apply the Strong Acid-Base Calculations concept. If you need more Strong Acid-Base Calculations practice, you can also practice Strong Acid-Base Calculations practice problems.

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Based on our data, we think this problem is relevant for Professor Marin's class at UCF.