For this problem, we have to calculate the pH of 0.02 M KOH
KOH is a strong base (hydroxide of a Group 1A metal) which dissociates as:
KOH (aq) → K+ (aq) + OH- (aq)
Calculating the [OH-]:
[OH-] = 0.02 M
Calculate the pH of a 0.02 M solution of KOH.
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