We’re being asked to determine the volume of HCl based on a neutralization reaction. The reaction of KOH with HCl is as follows:
KOH(aq) + HCl(aq) → KCl (aq) + 2 H2O(I)
It required 25 mL of 0.1 M KOH solution to neutralize 0.5 M HCl solution. For this problem, we need to:
Recall that molarity is given by:
What volume of a 0.5 M aqueous solution of HCl is needed to reach the equivalence point in a titration of 25 mL of a 0.1 M aqueous solution of potassium hydroxide (KOH)?
A. 5 mL
B. 25 mL
C. 50 mL
D. 500 mL
E. none of the above
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