We’re being asked to determine the correct order of halo-substituted acetic acids from the least acidic on the left to the most acidic on the right.
Acetic acid has a formula of CH3COOH or CH3CO2H. Let’s draw the Lewis structure of acetic acid using the following steps:
Step 1: Determine the central atom in this molecule.
Step 2: Calculate the total number of valence electrons present.
Step 3: Draw the Lewis structure for the molecule.
Which of the following shows the correct order of halo-substituted acetic acids from the least acidic on the left to the most acidic on the right?
A. FCH2CO2H < BrCH2CO2H < ClCH2CO2H < ICH2CO2H
B. ICH2CO2H < BrCH2CO2H < ClCH2CO2H < FCH2CO2H
C. FCH2CO2H < ClCH2CO2H < BrCH2CO2H < ICH2CO2H
D. ClCH2CO2H < BrCH2CO2H < ICH2CO2H < FCH2CO2H
E. ICH2CO2H < BrCH2CO2H < FCH2CO2H < ClCH2CO2H
Frequently Asked Questions
What scientific concept do you need to know in order to solve this problem?
Our tutors have indicated that to solve this problem you will need to apply the Identifying Acids and Bases concept. You can view video lessons to learn Identifying Acids and Bases. Or if you need more Identifying Acids and Bases practice, you can also practice Identifying Acids and Bases practice problems.