Problem: Which of the following shows the correct order of halo-substituted acetic acids from the least acidic on the left to the most acidic on the right?A. FCH2CO2H < BrCH2CO2H < ClCH2CO2H < ICH2CO2HB. ICH2CO2H < BrCH2CO2H < ClCH2CO2H < FCH2CO2HC. FCH2CO2H < ClCH2CO2H < BrCH2CO2H < ICH2CO2HD. ClCH2CO2H < BrCH2CO2H < ICH2CO2H < FCH2CO2HE. ICH2CO2H < BrCH2CO2H < FCH2CO2H < ClCH2CO2H

FREE Expert Solution

We’re being asked to determine the correct order of halo-substituted acetic acids from the least acidic on the left to the most acidic on the right.

Acetic acid has a formula of CH3COOH or CH3CO2H. Let’s draw the Lewis structure of acetic acid using the following steps:

Step 1: Determine the central atom in this molecule.
Step 2: Calculate the total number of valence electrons present.
Step 3: Draw the Lewis structure for the molecule.

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Problem Details

Which of the following shows the correct order of halo-substituted acetic acids from the least acidic on the left to the most acidic on the right?

A. FCH2CO2H < BrCH2CO2H < ClCH2CO2H < ICH2CO2H

B. ICH2CO2H < BrCH2CO2H < ClCH2CO2H < FCH2CO2H

C. FCH2CO2H < ClCH2CO2H < BrCH2CO2H < ICH2CO2H

D. ClCH2CO2H < BrCH2CO2H < ICH2CO2H < FCH2CO2H

E. ICH2CO2H < BrCH2CO2H < FCH2CO2H < ClCH2CO2H