For this problem, we have to calculate the vapor pressure of the solution with 0.5 mol of solute at 275 g hexane (C_{6}H_{14})

The vapor pressure of a solution prepared by adding a nonvolatile solute to a volatile solvent is calculated using this formula:

$\overline{){{\mathrm{P}}}_{{\mathrm{sol}}}{}{=}{}{{\mathrm{P}}}_{{\mathrm{solvent}}}^{{\mathrm{o}}}{\xb7}{{\mathrm{X}}}_{{\mathrm{solvent}}}}$

We will **need the mole fraction of hexane **to calculate the vapor pressure of solution.

**Mole fraction is defined as:**

$\overline{){\mathrm{mole}}{}{\mathrm{fraction}}{}\left(\mathrm{X}\right){}{=}{}\frac{\mathrm{moles}\mathrm{of}\mathrm{a}\mathrm{component}}{\mathrm{total}\mathrm{moles}}}$

For this problem, follow the steps

**Step 1. **Calculate moles of hexane

**Step 2. **Calculate mole fraction of hexane

**Step 3.** Calculate the vapor pressure

**Step 1. **Mole fraction of hexane can be calculated by dividing the moles of hexane by the total moles

Calculate the vapor pressure of a solution prepared by dissolving 0.500 mol of a non-volatile solute in 275 g of hexane (M = 86.18 g/mol) at 49.6°C. P°_{hexane} = 400.0 torr at 49.6°C.

A) 54 torr

B) 154 torr

C) 246 torr

D) 346 torr

E) 400. torr

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Based on our data, we think this problem is relevant for Professor Wiegand's class at UW-SEATTLE.