Ch.12 - SolutionsWorksheetSee all chapters
All Chapters
Ch.1 - Intro to General Chemistry
Ch.2 - Atoms & Elements
Ch.3 - Chemical Reactions
BONUS: Lab Techniques and Procedures
BONUS: Mathematical Operations and Functions
Ch.4 - Chemical Quantities & Aqueous Reactions
Ch.5 - Gases
Ch.6 - Thermochemistry
Ch.7 - Quantum Mechanics
Ch.8 - Periodic Properties of the Elements
Ch.9 - Bonding & Molecular Structure
Ch.10 - Molecular Shapes & Valence Bond Theory
Ch.11 - Liquids, Solids & Intermolecular Forces
Ch.12 - Solutions
Ch.13 - Chemical Kinetics
Ch.14 - Chemical Equilibrium
Ch.15 - Acid and Base Equilibrium
Ch.16 - Aqueous Equilibrium
Ch. 17 - Chemical Thermodynamics
Ch.18 - Electrochemistry
Ch.19 - Nuclear Chemistry
Ch.20 - Organic Chemistry
Ch.22 - Chemistry of the Nonmetals
Ch.23 - Transition Metals and Coordination Compounds
Problem

What is the molality of a solution of 18% by mass cadmium sulfate, CdSO4 (molar mass = 208.46 g/mol) by mass?

A) 0.53 m

B) 0.44 m

C) 0.86 m

D) 2.10 m

E) 1.05 m

Solution

We’re being asked to calculate for the molality of 18 % by weight aqueous solution of CdSO4

When calculating for molality, we use the following equation:

molality = mol solutekg solvent


We will calculate the molality of the solution using the following steps:

Step 1Determine the composition of the solution.
Step 2Calculate the molality of the solution.


Step 1. Determine the composition of the solution.

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