For this problem, we have to solve for the concentration of iodide ions in a saturated solution of lead (II) iodide
Recall that Ksp is an equilibrium constant related to slightly soluble ionic compounds.
The dissociation of slightly soluble PbI2 in solution is as follows:
PbI2(s) ⇌ Pb2+(aq) + 2 I–(aq)
We can construct an ICE table for this dissociation. Remember that solids are ignored in the ICE table and Ksp expression.
The concentration of iodide ions in a saturated solution of lead (II) iodide is __________ M. The solubility product constant of is Pbl2 is 1.4 x 10-8.
A) 3.0 x 10-3
B) 3.8 x 10-4
C) 1.5 x 10-3
D) 3.5 x 10-9
E) 1.4 x 10-8
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