We’re being asked to** calculate the Avogadro's number using the radius, density and formula weight of Pd metal**

Recall that Avogadro's number is given by:

$\overline{){{\mathbf{N}}}_{{\mathbf{A}}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}\frac{\mathbf{number}\mathbf{}\mathbf{of}\mathbf{}\mathbf{atoms}}{\mathbf{1}\mathbf{}\mathbf{mol}}}$

In this case, we have to find the number of atoms in an FCC crystal and the number of moles present using the provided data

A **face-centered cubic lattice**** contains an atom in each of the face of the cube and an atom in each of the corners****.** It looks like this:

Pd crystallizes with a face-centered cubic unit cell. It has a density of 6.00 g/cm^{3} and a radius of 138 pm and a FW of 106.42 g/mol. Use these data to estimate Avagadro’s number.

A. 6.0 x 10^{23}

B. 5.9 x 10^{23}

C. 3.1 x 10^{23}

D. 11.9 x 10^{23}

E. 6.0 x 10^{24}