# Problem: Butane (C4H10) has a heat of vaporization of 22.44 kJ/mol and a normal boiling point of -0.40°C. A 300. mL sealed flask contains 0.620g of butane at -21.0°C. How much liquid butane is present?A. 0.375g B. 0.475g C. 0.245g D. 0.620g E. no liquid left

###### FREE Expert Solution

We are asked how much liquid butane is present in a 300. mL sealed flask contains 0.620g of butane at -21.0°C

We go through the following steps to solve the problem:

Step 1. Calculate the vapor pressure at -21.0 °C

Step 2. Calculate the mass in the gas phase

Step 3. Calculate the mass in the liquid phase

Step 1. Calculate the vapor pressure at -21.0 °C

For this part, we can use the Clausius-Clapeyron Equation:

where:

P1 = vapor pressure at T1

P2 = vapor pressure at T2

ΔHvap = heat of vaporization (in J/mol)

R = gas constant (8.314 J/mol•K)

T1 and T2 = temperature (in K).

84% (400 ratings) ###### Problem Details

Butane (C4H10) has a heat of vaporization of 22.44 kJ/mol and a normal boiling point of -0.40°C. A 300. mL sealed flask contains 0.620g of butane at -21.0°C. How much liquid butane is present?

A. 0.375g

B. 0.475g

C. 0.245g

D. 0.620g

E. no liquid left