We're being asked to determine the rate law for the reaction below:
P4O10(aq) + 6 H2O(l) → 4 H3PO4(aq)
Recall that the rate law only focuses on the reactant concentrations and has a general form of:
k = rate constant
A & B = reactants
x & y = reactant orders
We can determine the rate order and rate law of reaction using the following methods:
For the reaction P4O10(aq) + 6H2O(l) -> 4H3PO4(aq) the rate law is
A. rate = k[P4O10][H2O]6
B. rate = k[P4O10][H2O]
C. rate = k[P4O10]
D. rate = k[P4O10]4
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