We're being asked to determine the mass percent of methanol in a mixture of water and methanol.

Recall that **mass percent** can be calculated as:

$\overline{){\mathbf{mass}}{\mathbf{}}{\mathbf{percent}}{\mathbf{}}{{\mathbf{CH}}}_{{\mathbf{3}}}{\mathbf{OH}}{\mathbf{=}}\frac{\mathbf{mass}\mathbf{}{\mathbf{CH}}_{\mathbf{3}}\mathbf{OH}}{\mathbf{total}\mathbf{}\mathbf{mass}}{\mathbf{x}}{\mathbf{100}}}$

A solution is made containing 12.6 g of methanol CH _{3}OH (32.04 g/mol) in 154 g of water. H_{2}0 (18.02 g/mol)

b) Calculate the mass percent of methanol:

a. 10.19%

b. 8.18%

c. 2.77%

d. 6.95%

e. 7.56%

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