Problem: Briefly answer the following questions.Nobelium (No) is a radioactive metal element that does not occur naturally. Several experiments measuring the half-cell potentials for the reduction of No3+ to a lower oxidation state were performed at 25 °C, and the results are given below.No3+ (aq) + 1 e- → No2+ (aq)           ε°red = +1.45 V No3+ (aq) + 3 e- → No (s)               ε°red = -1.20 V Using the data given above, determine the half-cell potential for the reaction given below. Please circle your answer.No2+ (aq) + 2 e- → No (s)               ε°red = ???

FREE Expert Solution

We are asked to determine the half-cell potential for the reaction given below:

No²⁺ (aq) + 2 e^- → No (s)               ε°_red = ???

Recall: 

$\boxed{\mathbf{ }\mathbf{\Delta G}\mathbf{ }\mathbf{=}\mathbf{ }\mathbf{-}\mathbf{nF\epsilon }\mathbf{°}}$

where:

n = number of moles electrons

F = Faraday’s constant, 96485 C/mol e^- 

ε° = standard reduction potential