# Problem: Briefly answer the following questions.Nobelium (No) is a radioactive metal element that does not occur naturally. Several experiments measuring the half-cell potentials for the reduction of No3+ to a lower oxidation state were performed at 25 °C, and the results are given below.No3+ (aq) + 1 e- → No2+ (aq)           ε°red = +1.45 V No3+ (aq) + 3 e- → No (s)               ε°red = -1.20 V Using the data given above, determine the half-cell potential for the reaction given below. Please circle your answer.No2+ (aq) + 2 e- → No (s)               ε°red = ???

###### FREE Expert Solution

We are asked to determine the half-cell potential for the reaction given below:

No2+ (aq) + 2 e→ No (s)               ε°red = ???

Recall:

where:

n = number of moles electrons

F = Faraday’s constant, 96485 C/mol e-

ε° = standard reduction potential

87% (367 ratings) ###### Problem Details

Nobelium (No) is a radioactive metal element that does not occur naturally. Several experiments measuring the half-cell potentials for the reduction of No3+ to a lower oxidation state were performed at 25 °C, and the results are given below.

No3+ (aq) + 1 e→ No2+ (aq)           ε°red = +1.45 V

No3+ (aq) + 3 e→ No (s)               ε°red = -1.20 V

Using the data given above, determine the half-cell potential for the reaction given below. Please circle your answer.

No2+ (aq) + 2 e→ No (s)               ε°red = ???