# Problem: Ammonia reacts with oxygen according to the equation: 4 NH3(g) + 5 O2(g) =&gt; 4 NO(g) + 6 H2O(l). In an experiment in which the rate of change of nitric oxide is found to be 1.10 M/min, what is the rate of change of oxygen gas?A. 0.880 M/minB. –0.880 M/minC. –1.38 M/min D. –0.220 M/minE. –0.275 M/min

###### FREE Expert Solution

We're being asked to calculate the rate of change of oxygen gas if nitric oxide is found to be 1.10 M/min.

4 NH3(g) + 5 O2(g) → 4 NO(g) + 6 H2O(l)

Recall that the average rate of a reaction is given by:

where Δ[A] = change in concentration of reactants or products (in mol/L or M) and Δtime = change in time. We can simply do a rate-to-rate comparison based on the stoichiometric coefficients.

###### Problem Details

Ammonia reacts with oxygen according to the equation: 4 NH3(g) + 5 O2(g) => 4 NO(g) + 6 H2O(l). In an experiment in which the rate of change of nitric oxide is found to be 1.10 M/min, what is the rate of change of oxygen gas?

A. 0.880 M/min

B. –0.880 M/min

C. –1.38 M/min

D. –0.220 M/min

E. –0.275 M/min