We're being asked to calculate the rate of change of oxygen gas if nitric oxide is found to be 1.10 M/min.

4 NH_{3}(g) + 5 O_{2}(g) → 4 NO(g) + 6 H_{2}O(l)

Recall that the average rate of a reaction is given by:

$\overline{){\mathbf{Rate}}{\mathbf{=}}\frac{\mathbf{\u2206}\left[A\right]}{\mathbf{\u2206}\mathbf{}\mathbf{time}}}$

where **Δ[A]** = change in concentration of reactants or products (in mol/L or M) and **Δtime** = change in time. We can simply do a ** rate-to-rate comparison** based on the stoichiometric coefficients.

Ammonia reacts with oxygen according to the equation: 4 NH_{3}(g) + 5 O_{2}(g) => 4 NO(g) + 6 H_{2}O(l). In an experiment in which the rate of change of nitric oxide is found to be 1.10 M/min, what is the rate of change of oxygen gas?

A. 0.880 M/min

B. –0.880 M/min

C. –1.38 M/min

D. –0.220 M/min

E. –0.275 M/min

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