# Problem: A 1.00 x 10─3 M solution of CaBr 2 is added to 500 mL of a 2.00 M solution of Pb(NO3)2.Determine the solubility (in M) of PbBr 2 after 5.00 L of the CaBr 2 solution has been added to 500 mL of the 2.0 M Pb(NO3)2 solution. Show all work and circle your final answer.A. 1.51x10-4 MB. 0.181 M C. 1.39x10-4 MD. 9.10x10-4 ME. 1.96x10-4 M

###### FREE Expert Solution

We’re being asked to determine the solubility (in M) of PbBr2 after 5.00 L of the 1.00x10-3 M of the CaBr2 solution has been added to 500 mL of the 2.0 M Pb(NO3)2.

We’re going to calculate the solubility of PbBr2 using the following steps:

Step 1: Calculate the moles of Pb2+ from Pb(NO3)2.
Step 2: Calculate the moles of Br- from CaBr2.
Step 3: Determine the excess and calculate the concentration of the remaining excess reactant.
Step 4: Create an ICE chart for the dissociation of PbBr2.
Step 5: Calculate the solubility of PbBr2. ###### Problem Details

A 1.00 x 10─3 M solution of CaBr 2 is added to 500 mL of a 2.00 M solution of Pb(NO3)2.

Determine the solubility (in M) of PbBr 2 after 5.00 L of the CaBr 2 solution has been added to 500 mL of the 2.0 M Pb(NO3)2 solution. Show all work and circle your final answer.

A. 1.51x10-4 M

B. 0.181 M

C. 1.39x10-4 M

D. 9.10x10-4 M

E. 1.96x10-4 M