Under constant pressure conditions, a 107 g block of metal at 125°C is added to a mixture of 120 g of water and 22 g of ice at 0°C. As a result, the ice melts completely and the temperature of the water increases to 7°C.
Hydrochloric acid reacts with the metal (denoted M) according to the following reaction:
2M (s) + 6HCl (aq) → 2MCl 3 (aq) + 3H 2 (g) ΔH rx° = -1049 kJ/mol
Suppose the mixture above is warmed to 25°C and then 0.10 mole of HCl is added. What is the new temperature of the water (in °C)? Show all work and circle your final answer.
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