We're being asked to determine the K or equilibrium constant for a reaction with ΔG° (standard free energy) of 13.3 kJ/mol at 125°C

For this problem, we can use the ** ΔG°-K equation** where:

$\overline{){\mathbf{\u2206}}{\mathbf{G}}{\mathbf{}}{\mathbf{=}}{\mathbf{}}{\mathbf{-}}{\mathbf{RTln}}\mathbf{\left(}\mathbf{K}\mathbf{\right)}}$

where ΔG is the free energy in J/mol K;

R is the gas constant (8.314 J/molK);

T is temperature in K;

and K as equilibrium constant

Given are:

The standard free energy change for a chemical reaction is +13.3 kJ/mol. What is the equilibrium constant for the reaction at 125 °C? (R = 8.314 J/K⋅mol)

a. 55.59

b. 29.11

c. 7.2x10^{-4}

d. 1.8x10^{-2}

e. 9.1x10^{-3}