Problem: The standard free energy change for a chemical reaction is +13.3 kJ/mol. What is the equilibrium constant for the reaction at 125 °C? (R = 8.314 J/K⋅mol) a. 55.59b. 29.11c. 7.2x10-4d. 1.8x10-2e. 9.1x10-3

FREE Expert Solution

We're being asked to determine the K or equilibrium constant for a reaction with ΔG° (standard free energy) of 13.3 kJ/mol at 125°C

For this problem, we can use the ΔG°-K equation where:

G = -RTln(K)

where ΔG is the free energy in J/mol K; 

R is the gas constant (8.314 J/molK); 

T is temperature in K; 

and K as equilibrium constant

Given are:

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Problem Details

The standard free energy change for a chemical reaction is +13.3 kJ/mol. What is the equilibrium constant for the reaction at 125 °C? (R = 8.314 J/K⋅mol) 

a. 55.59

b. 29.11

c. 7.2x10-4

d. 1.8x10-2

e. 9.1x10-3